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11x^2-15x+4=0
a = 11; b = -15; c = +4;
Δ = b2-4ac
Δ = -152-4·11·4
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-7}{2*11}=\frac{8}{22} =4/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+7}{2*11}=\frac{22}{22} =1 $
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